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2x^2-x=78
We move all terms to the left:
2x^2-x-(78)=0
We add all the numbers together, and all the variables
2x^2-1x-78=0
a = 2; b = -1; c = -78;
Δ = b2-4ac
Δ = -12-4·2·(-78)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-25}{2*2}=\frac{-24}{4} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+25}{2*2}=\frac{26}{4} =6+1/2 $
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